Question 600314
13xx+13yy=49. I need to decide if it is an ellipse, parabola, hyperbola, or a circle. Once I decide I need to put into the right equation and be able to graph it.
<pre>
13·x² + 13·y² = 49

It's a circle because x² and y² have the same coefficient when they
are on the same side of the equation.

Divide through by 13

{{{13*x^2/13}}} + {{{13*y^2/13}}} = {{{49/13}}}

{{{(cross(13)x^2)/cross(13)}}} + {{{cross(13)y^2/cross(13)}}} = {{{49/13}}}


x² + y² = {{{49/13}}}  in the form x² + y² = r²

That's a circle with center at the origin and radius = {{{sqrt(49/13)}}}

That's a weird value for a radius.  It's like 1.941450687

But here's the graph:

{{{drawing(400,400,-3,3,-3,3,graph(400,400,-3,3,-3,3),
circle(0,0,sqrt(49/13)) )}}}

Edwin</pre>