Question 600281
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Let *[tex \Large b] represent the number of boys and *[tex \Large g] represent the number of girls.  Presuming for the sake of simplicity that there are no members of the class that are in some sort of gender transitional state where they are neither boy nor girl, we can say that the total number students in the class is *[tex \Large b\ +\ g].  The number of boys who wear glasses is *[tex \Large \frac{b}{2}].


The desired probability is then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\frac{b}{2}}{b\ +\ g}\  =\ \frac{b}{2(b\ +\ g)}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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