Question 599978
A traveller begins a journey at Sydney and while on this journey makes three overnight stops. On the fourth day she reaches her destination, 1200km from Sydney. If on each day of her journey she travels twice as far as the previous day, how far did she travel on her first day?
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Let d = the distance traveled on the 1st day
Then for each of the remaining 3 days she traveled 2d, 4d and 8d, respectively
The total distance = 1200 = d + 2d + 4d + 8d
15d = 1200
d = 80
So she traveled 80 km on the 1st day