Question 55844
ok this is the right problem now, please help to solve 3x-6y=9
6Y=3X-9
Y=(3X-9)/6......................1
x-2y=3
2Y=X-3
Y=(X-3)/2
X..................0.............3.................6..........ETC
Y=(3X-9)/6........-9/6...........0.................9/6....ETC
Y=(X-3)/2..........-3/2..........0.................3/2.....ETC...
SEE GRAPH BELOW
{{{ graph( 500, 500, -10, 10, -10, 10, (3*x-9)/6, (x-3)/2) }}}
please solve by graphing, thank you in advance nightowl!
BOTH THE GRAPHS COINCIDE.HENCE THE EQNS.ARE DEPENDENT.HENCE THERE ARE INFINTE SOLUTIONS.ANY POINT ON THE GRAPH IS A SOLUTION.VIZ..(3,0),(0,-1.5),(6,1.5)...ETC......IN GENEARAL..{X,(X-3)/2}FOR ANY VALUE OF X IS A SOLUTION.