Question 599344
Solve for x:
{{{Log[2](x) = 2}}} Rewrite in exponential form. If {{{Log[b](x) = y}}}, then {{{b^y = x}}} so...
{{{2^2 = x}}}
{{{x = 4}}}
Solve for b:
{{{Log[b](4) = 2/3}}} Rewrite in exponential form:
{{{b^(2/3) = 4}}} Raise both sides to the {{{3/2}}} power.
{{{(b^(2/3))^(3/2) = 4^(3/2)}}} Simplify.
{{{b = sqrt(4^3)}}}
{{{b = sqrt(64)}}}
{{{b = 8}}}