Question 599343
{{{(3x^2)/(27x)}}}


{{{(3x*x)/(3*9*x)}}}


{{{(highlight(3)*x*highlight(x))/(highlight(3)*9*highlight(x))}}}


{{{(cross(3)*x*cross(x))/(cross(3)*9*cross(x))}}}


{{{x/9}}}



So {{{(3x^2)/(27x)}}} completely simplifies to {{{x/9}}}


In other words, {{{(3x^2)/(27x)=x/9}}} for all values of x where {{{x<>0}}}