Question 599062
2+log base 4 (x) + 2log base 4 (y) - log base 4 (z-2)
Which is
2+log base 4 (x) + log base 4 (y^2) - log base 4 (z-2).
Adding logs is multiply, minus is dividing, so we have
{{{2+log4((xy^2)/(z-2))}}}