Question 599059
3x^2-14x-24 is a polynomial

but
3x^2-14x-24=0 is an equation

comparing this with general quadratic equation ax^2+bx+c=0 we get
a=3, b=-14, c=-24

you can now solve it by using the formula but I prefer to use 'spliting the middle term' method

using this method, the given equation can be written as
{{{3x^2-18x+4x-24=0}}}
3x can be taken out as common from first two terms and 4 from the last two,so the equation becomes
{{{3x*(x-6)+4*(x-6)=0}}}
taking (x-6) common from the two terms,we get
(x-6)(3x+4)=0 
Now either (x-6)=0, OR (3x+4)=0

solving these equations,
either x=6 OR x=-4/3


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