Question 598961
y=-x^2-3x+4 to help solve the inequality -x^2-3x+4>0 ? 
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{{{graph(400,400,-10,10,-10,10,-x^2-3x+4)}}}
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Find the x-intercepts:
-x^2-3x+4 = 0
x^2+3x-4 = 0
(x+4)(x-1) = 0
x = 1 or x = -4
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The "greater than zero" interval is -4< x <1
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Cheers,
Stan H.