Question 598910
trying to graph the following, but I've never seen something like this before: 
(x-2)^2+(y-3)^2/64=1
This is an equation of an ellipse with vertical major axis.
Its standard form: (x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k)=(x,y) coordinates of center.
For given equation: (x-2)^2+(y-3)^2/64=1
center: (2,3)
a^2=64
a=√64=8
vertices: (2,3±a)=(2,3±8)=(2,-5) and (2,11)
..
b^2=1
b=1
end-points of minor axis: (2±b,3)=(2±1,3)=(1,3) and (3,3)
..
Foci:
c^2=a^2-b^2=64-1=63
c=√63≈7.9
Foci:(2,3±c)=(2,3±7.9)=(2,-4.9) and (2,10.9)
see graph below:
y=(64-64(x-2)^2)^.5+3
{{{ graph( 300, 300, -10, 10, -10, 10, (64-64(x-2)^2)^.5+3,-(64-64(x-2)^2)^.5+3) }}}