Question 598803
Expand:
{{{Log[7](7x^2y^3/z)}}} First, apply the "quotient rule" for logarithms: {{{Log[b](M/N) = Log[b](M)-Log[b](N)}}} to get:
{{{Log[7](7x^2y^3)-Log[7](z)}}} Next, apply the "product rule" for logarithms: {{{Log[b](M*N) = Log[b](M)+Log[b](N)}}} to get:
{{{Log[7](7)+Log[7](x^2)+Log[7](y^3)-Log[7](z)}}} Now apply the "power rule" for logarithms: {{{Log[b](M^n) = nLog[b](M)}}} to get:
{{{Log[7](7)+ 2Log[7](x)+3Log[7](y)-Log[7](z)}}} Finally, substitute {{{Log[7](7) = 1}}}
{{{1+2Log[7](x)+3Log[7](y)-Log[7](z)}}}