Question 598691
#1. (y - 7)^2
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{{{(y-7)^2=(y-7)*(y-7)}}}
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Distribute each term in the first binomial over the terms in the second binomial. You will end up with a 2nd degree polynomial with four terms.
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{{{(y-7)^2=(y)(y)+(y)(-7)+(-7)(y)+(-7)(-7)}}}
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Combine the two (-7y) terms.
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{{{(y-7)^2=y^2-7y-7y+49}}}
{{{(y-7)^2=y^2-14y+49}}}
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#2. (y^2 - 7y + 4)(4 + 1)
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Did you really mean (4+1) in the second term? That would simplify to 5? have
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{{{(y^2 - 7y + 4)(4 + 1)}}}
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Simplify.
{{{(y^2 - 7y + 4)(5)}}}
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Distribute the 5 over every term in the first polynomial. (We're going to the left this time because there is only one term to distribute.
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{{{5y^2 - 35y + 20}}}
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#3. Correct
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I hope this helps. Feel free to email via gmail if you have questions about my solutions. If #2 is a typo, email me or re-post for all tutors.
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Ms.Figgy
math.in.the.vortex@gmail.com