Question 598559
The strontium-90 in a nuclear reactor decays continuously.
 If 200 mg is present initially, the amount present after t years is given by A(t) = 200e^-0.0248t. Find, to nearest hundredth, the amount left after 50 years.
:
50 yrs means t = 50
A = {{{200*e^(-.0248*50)}}}
:
A = {{{200*e^(-1.24)}}}
A = 200 * .289384
A = 57.88 mg after 50 yrs