Question 598607
express {{{5sqrt3 - 5i}}} in polar form.
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{{{r = sqrt((5sqrt(3))^2 + 5^2) = 10}}}
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Angle = arctan(-5/(5sqrt(3)) = -sqrt(3)/3
Angle = 11pi/6
--> 10(cos(11pi/6) + isin(11pi/6))