<PRE><B>Question 598640</B>
Find the coordinates of the point that lies three fourths of the way from 
(10, -8) to (6, 0)
a) (8, -4) b) (9, -2) c) (7, -2) d) (9, -6)
-----------------------------------------------------
Let (x,y) be that point:
x = 10 + (3/4)(6-10) = 10 + (3/4)(-4) = 10-3 = 7
---
y = -8 + (3/4)(0-(-8)) = -8 + (3/4)(8) = -8+6 = -2
---
Ans: (7.-2)
=================
Cheers,
Stan H.
=================</PRE>