Question 598352
{{{(x^2-x-6)/(x^2-4)}}}


{{{((x-3)(x+2))/(x^2-4)}}}


{{{((x-3)(x+2))/((x-2)(x+2))}}}


{{{((x-3)*highlight((x+2)))/((x-2)*highlight((x+2)))}}}


{{{((x-3)*cross((x+2)))/((x-2)*cross((x+2)))}}}


{{{(x-3)/(x-2)}}}


So {{{(x^2-x-6)/(x^2-4)}}} fully simplifies to {{{(x-3)/(x-2)}}}


In other words, {{{(x^2-x-6)/(x^2-4)=(x-3)/(x-2)}}} for all values of x where {{{x<>2}}} or {{{x<>-2}}}