Question 598277
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You just take the FOIL process backwards.


Note that the sign on the constant term is positive so the signs in the two factors have to be the same.  Since the sign on the first degree term is negative, the two signs must be negative.


The only way to make 5 from two negative factors is -1 times -5.  The only way to make 3 is 3 times 1.


So your only two possibilities are:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (3x\ -\ 5)(x\ -\ 1)]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (3x\ -\ 1)(x\ -\ 5)]


Use FOIL to multiply them out to figure out which one is the correct one, if either (i.e. don't forget the possibility that the original trinomial is prime over the real numbers)


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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