Question 597907
simply the expression: [x^2+4x+4/x-2] * [-(x-2)/3x+6]
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Factor:
[(x+2)^2/(x-2)] * [-(x-2)/(3(x+2)]
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Cancel any factor common to a numerator and a denominator,
such as (x+2), (x-2), to get:
(x+2)/1*[-1/3]
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= (-1/3)(x+2)
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Cheers,
Stan H.
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