Question 597635
<pre>

cos(&#952;)[sin(&#952;) + {{{(cos^2(theta))/sin(theta)}}}] = cot(&#952;)

Get an LCD of sin(&#952;) in the brackets:

cos(&#952;)[{{{sin(theta)*sin(theta)/sin(theta)}}} + {{{(cos^2(theta))/sin(theta)}}}]

cos(&#952;)[{{{sin^2(theta)/sin(theta)}}} + {{{(cos^2(theta))/sin(theta)}}}]

cos(&#952;)[{{{(sin^2(theta) + cos^2(theta))/sin(theta)}}}]

cos(&#952;)[{{{1/sin(theta)}}}]

{{{cos(theta)/sin(theta)}}}

cot(&#952;)

Edwin</pre>