Question 597464
Hi, there--
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The form for the equation for a circle in standard form is
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{{{(x-h)^2+(y-k)^2=r^2}}}
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where
(h,k)=(0,0) is the center of the circle and r = sqrt(13) is the radius.
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Substitute your values for the center and radius of the circle into the equation.
{{{(x-0)^2+(y-0)^2=(sqrt(13))^2}}}
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Simplify.
{{{x^2+y^2=13}}}
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That's it. Feel free to email me via gmail if the explanation is unclear.
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Ms.Figgy
matth.in.the.vortex@gmail.com