<PRE><B>Question 597473</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_{64}(x)\ =\ \frac{1}{3}]


Use the definition of the logarithm function:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(x)\ =\ y\ \Leftrightarrow\ b^y\ = x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 64^{\small\frac{1}{3}}\ =\ \sqrt[3]{64}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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