Question 597047
Please help me solve these identities! tan[cos^-1(-square root of 3/2)] and the answer in the book is -square root of 3/3.
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tan[cos^-1(√3/2)]
cos^-1(√3/2 is an angle whose cos=√3/2
This angle is π/6
so tan[cos^-1(√3/2)]
=tan π/6=√3/3