Question 596865
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The question presumes a linear model for your data.  You are given 2 data points:  11 am, 9 lawns and 1:30 pm, 14 lawns.


Let 0 time represent 11:00 am, and then since 1:30 pm is 2 and 1/2 hours later, let 2.5 time represent 1:30.


Now you have two ordered pairs:  (0,9) and (2.5,14).


Use the two-point form of an equation of a line to write an equation that models your data:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Once you have your equation simplified, use the slope (i.e. the coefficient on the independent variable) to answer part a.  Then solve your equation for the independent variable in terms of the dependent variable.  In this new form, the coefficient on the former dependent variable will be the answer to part b. (Once you convert it from hours to minutes, that is)


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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