Question 596753
Hi, there--
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We can use solve this system using the substitution method. 
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Rewrite the second equation in terms of y.
{{{y+3=0}}}
{{{y=-3}}}
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Substitute -3 for y in the first equation.
{{{5x+2y=-10}}}
{{{5x+2(-3)=-10}}}
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Simplify the equation and solve for x.
{{{5x+(-6)=-10}}}
{{{5x-6=-10}}}
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Add 6 to both sides of the equation.
{{{5x=-4}}}
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Divide both sides by 5.
{{{x=-(4/5)}}}
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The solution for this system is the ordered pair (-4/5, -3).
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CHECK your work by substituting this ordered pair into both equations.
{{{5x+2y=-10}}}
{{{5(-(4/5))+2(-3)=-10}}}
{{{(-4)+(-6)=-10}}}
{{{-10=-10}}}
Bingo!
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{{{y+3=0}}}

There is no x-term in this equation, so we only substitute the y-value.
{{{(-3)+3=0}}}
{{{0=0}}}
Perfect!
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That's it. Feel free to email if this explanation is unclear.
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Ms.Figgy
math.in.the.vortex@gmail.com