Question 596816


{{{(5y-2)^2}}} Start with the given expression.



{{{(5y-2)(5y-2)}}} Expand. Remember something like {{{x^2=x*x}}}.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(5y)-2)(highlight(5y)-2)}}} Multiply the <font color="red">F</font>irst terms:{{{(5*y)*(5*y)=25*y^2}}}.



{{{(highlight(5y)-2)(5y+highlight(-2))}}} Multiply the <font color="red">O</font>uter terms:{{{(5*y)*(-2)=-10*y}}}.



{{{(5y+highlight(-2))(highlight(5y)-2)}}} Multiply the <font color="red">I</font>nner terms:{{{(-2)*(5*y)=-10*y}}}.



{{{(5y+highlight(-2))(5y+highlight(-2))}}} Multiply the <font color="red">L</font>ast terms:{{{(-2)*(-2)=4}}}.



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So we have the terms: {{{25*y^2}}}, {{{-10*y}}}, {{{-10*y}}}, {{{4}}} 



{{{25*y^2-10*y-10*y+4}}} Now add every term listed above to make a single expression.



{{{25y^2-20y+4}}} Now combine like terms.



So {{{(5y-2)^2}}} FOILs to {{{25y^2-20y+4}}}.



In other words, {{{(5y-2)^2=25y^2-20y+4}}}.