Question 596752
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Let the measure of the second longest side be represented by *[tex \LARGE x].  The the measure of the longest side must be represented by *[tex \LARGE x\ + 7].


Since the perimeter is the sum of the measures of all three sides, the short side must measure *[tex \LARGE 30\ -\ x\ -\ (x\ +\ 7)\ =\ 23\ -\ 2x]


Use Pythagoras:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ (23\ -\ 2x)^2\ =\ (x\ +\ 7)^2]


Solve for *[tex \LARGE x].  Then calculate *[tex \LARGE 23\ -\ 2x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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