<PRE><B>Question 596404</B>
find the complex zeros of the polynomial function write f in the factored form. x^3+216 

so far I have done:

x^3 + 6^3

(a+b)(a^2-ab+b^2) = (x+6)(x^2-6x+36)

quadratic formula: -b plus or minus square root (b^2 - 4 * a * c)/2

6 +- square root (36 - 144)/2

I am confused on the simplified answer not the math in general so would I leave 
6 +- square root 108 in that form divided by 2 or what?
-----------
-------
If you meant x^3 + 216 = 0, then
{{{(x+6)*(x^2 - 6x + 36) = 0}}}
x = -6
-----
{{{x^2 - 6x + 36 = 0}}}
*[invoke solve_quadratic_equation 1,-6,36]
========================
{{{x = 3 +- 3sqrt(3)}}}
</PRE>