Question 6874
the solution to this problem is called 'permutations'.

the number of arrangements you can make with n different symbols, is equal to n!. That is called the 'faculty' of n, defined as n! = n x (n-1) x ... 2 x 1.
This means that you are right!


The word in you problem counts 5 symbols, so you can make 120 arrangements with it.

greets,
Pieter
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