Question 596354
    Air Pollution the amount of mitrogen dioxide A in parts per million (PPM) that presetn in the air in the city of homer on a certain day in june is modeled by the function a(t)=-2t^2+32t+12
    Where t is the number of hours after 6:00 am use this function to find the time at which the nitrogen dioxide level was at its maximum.
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Because the coefficient associated with the t^2 term is negative, we KNOW that it is a parabola that opens downwards.  So, the vertex is the max.
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t-value at max:
t = -b/(2a)
t = -32/(2(-2))
t = -32/(-4)
t = 8 hours
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6:00 am + 8 hours = 2 pm