Question 596339
    A chemist would like to dilute a 20-cc solution that is 5% acid to one that is 3% acid. How much water must be added to accomplish this task?
.
Let x = amount (cc) of water added
then
.05(20) = .03(20 + x)
1 = 0.6 + .03x
0.4 = .03x
40/3 = x
13 and 1/3 cc = x
or
13.333 cc = x