Question 55656
{{{x^2=5x+36}}}  Set the problem =0
{{{x^2-5x-36=5x-5x+36-36}}}
{{{x^2-5x-36=0}}}  Factor.
(x___)(x___)  Two numbers that multiply to give you -36, but add to give -5 are -9 and +4, -9*4=-36 and -9+4=-5
(x-9)(x+4)=0  Use the zero product property and set each parenthesis=0
x-9=0 
x=9
and 
x+4=0
x=-4
x={-4,9}
Check
{{{(-4)^2=5(-4)+36}}}
{{{16=-20+36}}}
{{{16=16}}}  -4 checks out.
{{{(9)^2=5(9)+36}}}
{{{81=45+36}}}
{{{81=81}}} 9 checks out also, we're right!!!
Happy Calculating!!!