Question 596212
(height) = -(half the gravitational acceleration times the time squared) + (initial velocity times the time) + (initial height)


h = -16t^2 + 1000t + 50


the max height is on the axis of symmetry ___ t = -1000 / [2(-16)] = 125/4
___ substitute the time into the equation to find the height


the quadratic formula is ___ {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


remember that the equation must equal zero to use the formula
___ you may have to subtract the height from the expression to accomplish this


1. set h=0 in height equation, use quadratic formula to solve


2. (and 6) plug time into height formula


3. (and 4) height is 2000, but equation must equal zero to use quadratic formula (see above comments)


5. see above comments