Question 55642
factor completly   
{{{128x^3-54}}}  Factor the GCF out
{{{2(64x^3-27)}}}  Realize that you have the difference of cubes.
{{{2(4x*4x*4x-3*3*3)}}}
{{{2((4x)^3-(3)^3)}}}  Use the formula for factoring the diffence of cubes:{{{highlight(u^3-v^3=(u-v)(u^2+uv+v^2))}}}  Your u=4x and v=3
{{{2(4x-3)((4x)^2+(4x)(3)+(3)^2)}}}
{{{highlight(2(4x-3)(16x^2+12x+9))}}}
Happy Calculating!!!