Question 596123
{{{ 9x^2 + 6x  = -1 }}}
{{{ 9x^2 + 6x + 1 = 0 }}}
This is in the form {{{ ax^2 + b*x + c = 0 }}}
The quadratic formula is
{{{ x = (-b +- sqrt( b^2 - 4*a*c )) / (2*a) }}}
{{{ a = 9 }}}
{{{ b = 6 }}}
{{{ c = 1 }}}
{{{ x = ( -6 +- sqrt( 6^2 - 4*9*1 )) / (2*9) }}} 
{{{ x = ( -6 +- sqrt( 36 - 36 )) / 18 }}}
{{{ x = ( -6 +- sqrt( 0 )) / 18 }}} 
{{{ x =  -(6 / 18) }}}
{{{ x = -(1/3) }}} answer
check:
{{{ x + 1/3 = 0 }}}
{{{ 3x + 1 = 0 }}}
This is a double root, so
{{{ ( 3x + 1 )*( 3x + 1 ) = 0 }}}
{{{ 9x^2 + 6x + 1 = 0 }}}
OK