Question 596140
How do you solve radical equations such as:
(6-square root 10)(2+square root 10)
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There's no equal sign, so it's not an equation. Also, there's no variable to solve for.
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(6-square root 10)(2+square root 10)
You can multiply the 2 binomials, same way as any other 2.
{{{(6-sqrt(10))(2+sqrt(10))}}}
= {{{6*2 + 6sqrt(10) - 2sqrt(10) - 10}}}
= {{{2 + 4sqrt(10)}}}