Question 596117
The general form for a hyperbola is:
{{{(x-h)^2/a^2 - (y-k)^2/b^2 = 1}}} (horizontally-oriented)
or
{{{(y-k)^2/a^2 - (x-h)^2/b^2 = 1}}} (vertically-oriented)
The center of the hyperbola, in both cases, is the point (h, k)<br>
Except for the +'s in your numerators, your equation is already in this form. All you have to do is rewrite the additions as equivalent subtractions:
{{{(x-(-3))^2/64 - (y-(-9))^2/25 = 1}}}
This makes the center: (-3, -9)