Question 596074
Hi, there--
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If {{{f(x)=e^x}}}, then {{{f(1)=e^1=e}}}.
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Raising any number to the 1st power is always equal to the number itself so e raised to the 1st power is simply e.
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If {{{g(x)=ln(x)}}}, then {{{g(1)=ln(1)=0}}}.
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The natural log function is the reciprocal of {{{f(x)=e^x}}}.
The natural log of 1 is zero because raising any number (including e) to the zero power is 1.
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Hope this helps! Feel free to email if you still have questions.
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Ms.Figgy
math.in.the.vortex@gmail.com