Question 596044
8s to the second power t to the thirteenth power over-2st to the 5 power= -4st to the eighth power . What happen to the s to the second power in this problem.
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[8s^2t^13] / [-2st^5]
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= (8/-2)(s^2/s)(t^13/t^5)
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= -4st^8
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Cheers,
Stan H.
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