Question 596010
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All of your factoring problems have correct answers.


The simplify problem  is wrong.  You are multiplying two binomials, so use the FOIL process.  Start over and do each multiplication carefully.


The set is just the set of all odd integers.



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ S\ =\ \left{n\,|\,\forall\,i\,\in\,\mathbb{Z},\,n\ =\ 2i\ -\ 1\right}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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