Question 596016
# 1


You're on the right track. Now foil/expand, simplify and get into standard form


{{{4x(x-2)+3(x+2)=4(x+2)(x-2)}}}


{{{4x(x-2)+3(x+2)=4(x^2-4)}}}


{{{4x^2-8x+3x+6=4x^2-16}}}


{{{4x^2-8x+3x+6-4x^2+16=0}}}


{{{-5x+22=0}}}


The x squared terms cancel and we're left with a linear equation. I'll let you solve this. Tell me what you get.


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# 2


The 6 is in the numerator of the second fraction (in step 2).


So it should stay in the numerator. You can multiply it with the 10 in the numerator of the first fraction to get 10*6 = 60


So you'll end up with 


60(b-5)/15(b-5)


which can be simplified further (I'll let you take over from here. Let me know what you get)