Question 595890
If y=x^2-4x-2 and y = x-2, then we can say 



x - 2 = x^2-4x-2



This is because the two are both simultaneously equal to y. So they must be equal to each other.


From here, solve for x



{{{x - 2 = x^2-4x-2}}}


{{{0 = x^2-4x-2 - x +2}}}


{{{0 = x^2-5x}}}


{{{x^2-5x = 0}}}


{{{x(x-5) = 0}}}


{{{x=0}}} or {{{x-5 = 0}}}


{{{x=0}}} or {{{x=5}}}


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If x = 0, then y = x-2 = 0-2 = -2


So if x = 0 then y = -2


So one ordered pair solution is (0, -2)



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If x = 5, then y = x-2 = 5-2 = 3


So when x = 5, the value of y is y = 3


So another ordered pair solution is (5, 3)