Question 595797
Code:
1st Number: 1, 2, 3, 4, 6, 7, 8, 9, 0 (9 possible combos)
2nd Number: 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 (10 possible combos)
3rd Number: 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 (10 possible combos)
4th Number: 1, 3, 5, 7, 9 (5 possible combos)

So to calculate number of codes:
Possible numbers of (1st Number*2nd Number*3rd Number*4th Number)
{{{9*10*10*5}}}
{{{4500}}}

There are 4500 different possible combinations