Question 595324
Expand the expression:
log(4)((3x^1)(y^3))
=log4(3x^1)+log4(y^3)
=log4(3)+log4(x)+3log4(y)
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Condense:
I assumed you left out a "+" sign in given expression
log(7)9+log(7)55
=log7(9*55)
=log7(495)≈3.189
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Evaluate log(12)782 to three decimal places.
log(12)782
using calculator and change of base formula:
log(782)/log(12)≈2.681

Use the change-of-base formula to evaluate the expression: 
log(4)7
=log(7)/log(4)≈1.404
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Find the inverse function of 
y=log(5)x
interchane x and y, then solve for y
x=log5(y)
y=5^x