Question 595513
{{{x(x-1)=6}}}


{{{x^2-x=6}}}


{{{x^2-x-6=0}}}


Now use the quadratic formula to solve for x.


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-1)+-sqrt((-1)^2-4(1)(-6)))/(2(1))}}}


{{{x = (1+-sqrt(1-(-24)))/(2)}}}


{{{x = (1+-sqrt(25))/2}}}


{{{x = (1+sqrt(25))/2}}} or {{{x = (1-sqrt(25))/2}}}


{{{x = (1+5)/2}}} or {{{x = (1-5)/2}}}


{{{x = 6/2}}} or {{{x = -4/2}}}


{{{x = 3}}} or {{{x = -2}}}



So the solutions are {{{x = 3}}} or {{{x = -2}}}