<PRE><B>Question 595163</B>
Andrew can paint the neighbors house 5 times as fast as Bailey. the year Andrew and Bailey worked together, it took them 1 day.
 How long would it take each to paint the house?
:
Let t = time for Andrew to paint the house
then
5t = time required by Bailey to do it
:
Write a shared work equation; the completed job = 1
{{{1/t}}} + {{{1/(5t)}}} = 1
multiply by 5t to clear the denominators, results:
5 + 1 = 5t
6 = 5t
t = 6/5
t = 1.2 days for Andrew
then
5(1.2) = 6 days for Bailey</PRE>