Question 595421
Factoring Quadratic formulas- Is this correct thus far?

5+2x^2=8x

2x^2-8x+5=0
a=2 b=-8 c=5
ac=2(5)=10 b=-8

Then i should find factors that multiply to give 10 & add to give -8 right ?

i only came up with the factors -5x(times)-2
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None of your operations are incorrect.
But, we don't factor quadratic formulas.
And, there is no quadratic formula.
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We factor the polynomials in order to solve the quadratic equation, if possible.
2x^2-8x+5=0
In this case, it can't be factored with integers, so we use the quadratic equation to solve it.
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*[invoke solve_quadratic_equation 2,-8,5]
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Tho the solver says it can be factored, it's not using integers.