Question 595379
{{{(1-3x)/(3x^2+14x-5)}}}


{{{-(-1+3x)/(3x^2+14x-5)}}}


{{{-(3x-1)/(3x^2+14x-5)}}}


{{{-(3x-1)/((3x-1)(x+5))}}}


{{{-(highlight((3x-1)))/(highlight((3x-1))(x+5))}}}


{{{-(cross((3x-1)))/(cross((3x-1))(x+5))}}}


{{{-1/(x+5)}}}


So {{{(1-3x)/(3x^2+14x-5)}}} completely simplifies to {{{-1/(x+5)}}}


In other words, {{{(1-3x)/(3x^2+14x-5)=-1/(x+5)}}} for all values of x where {{{x<>1/3}}} or {{{x<>-5}}}