Question 595364
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(6,-1\right)]. So this means that {{{x[1]=6}}} and {{{y[1]=-1}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-4,-3\right)].  So this means that {{{x[2]=-4}}} and {{{y[2]=-3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-3--1)/(-4-6)}}} Plug in {{{y[2]=-3}}}, {{{y[1]=-1}}}, {{{x[2]=-4}}}, and {{{x[1]=6}}}



{{{m=(-2)/(-4-6)}}} Subtract {{{-1}}} from {{{-3}}} to get {{{-2}}}



{{{m=(-2)/(-10)}}} Subtract {{{6}}} from {{{-4}}} to get {{{-10}}}



{{{m=1/5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(6,-1\right)] and *[Tex \LARGE \left(-4,-3\right)] is {{{m=1/5}}}