Question 595104
{{{(log(5, x))^2=2*log(5, x)}}} (the base is 5)
Itīs easier to see it if we change variables for a while, making
{{{y=log(5, x)}}}
Then, we can write it as
{{{y^2=2y}}} and then as
{{{y^2-2y=0}}} and as
{{{(y-2)y=0}}}
The solutions are {{{y=2}}} and {{{y=0}}} .
{{{y=2}}} means {{{log(5, x)=2}}} so {{{x=5^2=25}}} 
{{{y=0}}} means {{{log(5, x)=0}}} so {{{x=5^0=1}}}