Question 595164
What answer do I leave in absolute value when the equation of the other part does not factor.
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Not sure what you mean by that.  You don't leave anything in the ABS, you solve for x.
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Here's the problem I'm talking about:
|12x^2-x-2|=1
One side already factored is 
X=3/2 x=-1
The other side canbit be factored. Do I have to put 0 or just give the ones I got?
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|12x^2-x-2|=1
Case 1:
12x^2-x-2=1
{{{12x^2 - x - 3 = 0}}}
Solve for x using the quadratic eqn:
{{{x = 1/24 +- sqrt(145)/24}}}
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Case 2:
12x^2-x-2=-1
{{{12x^2 - x - 1 = 0}}}
Solve for x using the quadratic eqn:
x= -1/4, x = 1/3